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« Last post by Kenai on August 28, 2024, 11:13:16 AM »
Thanks for the reassurance.
So now just to figure out how that over 90 degree of coverage of SI piezo could possibly work. I have no idea. Does anybody ever really test if that coverage is more than 90 degrees (120 in fact from that piezo diagram)? It must be somehow trimmed out to that 86 degrees or so.
For fun, this is what HB support know about that:
"I do apologize but we are not able to give examples of this. We do no have exact angles or any information on how big the blind spot will be."
If we can assist you further on this subject or any other Humminbird related questions please feel free to email us again.
Good Boating and Fishing!
Tiffanie
Technical Support Representative
92
« Last post by TooTall on August 27, 2024, 04:08:19 PM »
Thanks for the update. I really appreciate your help. In my case it came with firmware 5.470 (worked perfect), and I installed 7.120 (After which my sonar didn't work). I tried to install 6.090 today, but it doesn't ask if I want to update the firmware when I install the SD card with 6.090. When I had 7.120 on the SD card, it automatically asked if I wanted to update the firmware when I inserted the SD card. Any ideas for where I go from here? Thanks so much for your help!
93
« Last post by navionic on August 27, 2024, 07:56:57 AM »
Hi,
I'm having the exact same issue. I am also in the process of emailing Humminbird, but so far they're suggestions haven't had any effect. Is there anyone able to provide me with an older version of the firmware for my 597 ci HD DI? Thanks, Matt
6.090 up https://dropmefiles.com/9jrgJ
94
« Last post by TooTall on August 26, 2024, 10:01:31 PM »
Hi,
I'm having the exact same issue. I am also in the process of emailing Humminbird, but so far they're suggestions haven't had any effect. Is there anyone able to provide me with an older version of the firmware for my 597 ci HD DI? Thanks, Matt
95
« Last post by rnvinc on August 26, 2024, 09:11:11 PM »
You are correct on all points ... The target cannot be discerned as to where it is in the thin slice beam of SI ... only distance to the target and strength of the return echo ... Here is a diagram that represents what you mention as targets the same distance from the transducer being “stacked together in the SI image ...  We see in the upper section of the diagram that fish 1 and fish 2 are the same distance from the transducer ... and we see in the lower section of the diagram ( SI image depiction) that fish 1 and fish 2 are shown stacked in the water column ... It’s the additional information (in the SI image) of the fish shadows cast against the bottom detail that discern where that fish is in the water column ... Rickie
96
« Last post by Kenai on August 26, 2024, 07:35:30 PM »
Thank you sir, so far it is clear. However, I'm still confused about that over 90 degree coverage of SI piezo. I will write it as simply as I can. English is not my first neither second language and technical terms are some problem for me. So bear with me.
I will simplify this example to just one piezo.
1. Let's say it is DI like piezo firing directly down with cone-shaped coverage. There is no way to tell on which side of that cone is fish (or some other return) present. We can just tell, if it is in the center or more to the side of the cone, by the strength of that return. We can't tell to which side. But we know exactly the depth of that fish in water column (distance of return) The same is true for 2D. Correct?
2. If that cone is oval-shaped as SI and still firing directly down (hypothetically) the same is true. We can't tell anything about fish/return position, but we narrowed it in one dimension (front aft) And we know exactly the depth of that fish in water column (distance of return) Correct ?
3. If we tilted that SI oval beam to the side, in the way, it covers the angle from vertical to horizontal on the right side (as it should in reality) our depth will change to distance from the boat. (in reality it is not horizontal distance, but this is good enough for our example) We still don't have any new information about return's position. The only way how we can tell it is on the right is by knowing that the beam covers only the right side. Time elapsed from ping to return is the function of distance. Shortest possible distance (and time) = directly under boat. Longest = parallel with water surface. Correct ?
That is the way I understand how SI works. Basically by beam shape and orientation. And the head unit interprets time of return as distance to side, instead of depth.
4. Now, how is possible to tell where the position of return is, if the cone is oriented like my pictures shows? From 60 to horizontal. (past 90 degree) So it covers more than right side only.
I believe if the SI coverage will be bigger than 90 degrees (from vertical to horizontal) then will be all echos with the same return time displayed on screen on top of each other blended together.
Correct ?
97
« Last post by rnvinc on August 25, 2024, 10:01:58 PM »
And just an added small note ...
The sequence of steps I listed are not exactly in the sequence of 2d piezo, DI piezo, left SI piezo, right SI piezo ...
I listed the piezos in that sequence for ease for understanding “ping sequence” ...
But the fact remains that only one piezo is operating at a time in its queue of the “ping sequence” ...
Rickie
98
« Last post by rnvinc on August 25, 2024, 09:50:38 PM »
The “overlap” under the boat of the left SI beam coverage and the right SI beam coverage are factual ... sort of ...
If … the left SI piezo “transmitted” at the same time as the right SI piezo “transmitted” = both would indeed overlap at the same time ... and the unit could not discern where a certain target was under the boat (as you supposed) ...
But because each piezo is operating indendently and only in its section (“transmit cycle”) of the “ping sequence” = the beam form diagram is correct ... SI beams do extend past vertical under the boat ...
But also because, the left SI “transmit cycle” and right SI “transmit cycle” are not operating at the same time = the unit is not confused on which piezo received which echo return ...
Rickie
99
« Last post by rnvinc on August 25, 2024, 09:42:52 PM »
This will be lengthy so bear with me to explain a “transmit cycle” to its basics ...
Let’s back up and explain “ping sequence” in a little more step by step process ... in the terms of what is a “transmit cycle” ...
(For explanation purposes we will say there are 4 piezoes in the “ping sequence” = 2d piezo, DI piezo, left SI piezo, right SI piezo) ... (there are actually 7 piezoes in a MEGA transducer but only the 4 listed are used in a given “ping sequence”) ...
Step 1. Processor tells 2d transmitter to fire ...
Step 2. 2d transmitter sends electrical signal to 2d piezo ...
Step 3. 2d piezo coverts electrical signal to mechanical signal (vibration) ...
Step 4. Mechanical signal vibration emits from transducer into water (sound pulse) ...
Step 5. 2d piezo listens for return echoes (no other piezoes are listening for return echoes) ...
Step 6. Return echoes return to 2d piezo ...
Step 7. 2d piezo coverts return echo vibrations back into electrical signals ...
Step 8. Electrical signals are sent to to processor ...
Step 9. Processor tells DI transmitter to fire ...
Step 10. DI transmitter sends electrical signal to DI piezo ...
Step 11. DI piezo coverts electrical signal to mechanical signal (vibration) ...
Step 12. Mechanical signal vibration emits from transducer into water (sound pulse) ...
Step 13. DI piezo listens for return echoes (no other piezoes are listening for return echoes) ...
Step 14. Return echoes return to DI piezo ...
Step 15. DI piezo coverts return echo vibrations back into electrical signals ...
Step 16. Electrical signals are sent to to processor ...
Step 17. Processor tells left SI transmitter to fire ...
Step 18. Left SI transmitter sends electrical signal to left SI piezo ...
Step 19. Left SI piezo coverts electrical signal to mechanical signal (vibration) ...
Step 20. Mechanical signal vibration emits from transducer into water (sound pulse) ...
Step 21. Left SI piezo listens for return echoes (no other piezoes are listening for return echoes) ...
Step 22. Return echoes return to left SI piezo ...
Step 23. Left SI piezo coverts return echo vibrations back into electrical signals ...
Step 24. Electrical signals are sent to to processor ...
Step 25. Processor tells right SI transmitter to fire ...
Step 26. Right SI transmitter sends electrical signal to left SI piezo ...
Step 27. Right SI piezo coverts electrical signal to mechanical signal (vibration) ...
Step 28. Mechanical signal vibration emits from transducer into water (sound pulse) ...
Step 29. Right SI piezo listens for return echoes (no other piezoes are listening for return echoes) ...
Step 30. Return echoes return to right SI piezo ...
Step 31. Right SI piezo coverts return echo vibrations back into electrical signals ...
Step 32. Electrical signals are sent to to processor ...
What we learn from this explanation of piezo “transmit cycles” and how each fits into the “ping sequence” is ...:
A. There is only 1 piezo operating (in its own “transmit cycle”) at a time in the “ping sequence” ...
B. The 8 steps in a certain piezo’s “transmit cycle” must complete before the processor will tell the next transmitter to initiate its “transmit cycle” ...
C. Therefore the unit “knows” exactly which piezo received a certain return echo ...
Rickie
100
« Last post by Kenai on August 25, 2024, 11:38:17 AM »
Yes Sir, that is exactly what I was thinking. But if that's so, there simply can't be any overlapped area. Because there will be no way to tell if the object is right or left from piezo which covers space on both sides. That fact I was trying to show on my drawings.
So If the beam diagram is correct, there must also be something else happening. Probably some filtering of used beam angle. That is most likely the reason, why SI don't cover space directly under the transducer and why HB said SI have 5 degree to each side of blind space under the boat. It is also shown in SI animations, where is visible a small uncovered area under the boat.
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